(3x-9)^2=2x(2x+29)

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Solution for (3x-9)^2=2x(2x+29) equation: 



(3x-9)^2=2x(2x+29)

We move all terms to the left:

(3x-9)^2-(2x(2x+29))=0



We calculate terms in parentheses: -(2x(2x+29)), so:

2x(2x+29)

We multiply parentheses

4x^2+58x

Back to the equation:

-(4x^2+58x)



We get rid of parentheses

-4x^2+(3x-9)^2-58x=0

We add all the numbers together, and all the variables

-4x^2-58x+(3x-9)^2=0

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